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WebDec 28, 2024 · 2. As my comment said, I guess the "\u0026" is an escaped string. That is, the real input should be something like. a = "\\u0026". with double backslashes to enter a real "\". Then, we may use json.loads as a tricky reverse function for re.escape, for example: WebPlease Login. Welcome to the Administration Control Panel for Hill and Smith Extranet. You must enter your login details below to gain access to the system. Please note: required fields are marked by *. Login. Username *. Password *. uses a. how can i make my feet softer
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WebView Janet Smith-Hill’s profile on LinkedIn, the world’s largest professional community. Janet has 2 jobs listed on their profile. See the complete profile on LinkedIn and discover … WebThe Smith Building is located between Swain Hall, Hill Hall, and New West and houses Women and Gender Studies, among other departments . However, despite her status as … WebIf you must use a regex, then you must escape the backslash that is in the Java string. Then you must escape both backslashes for regex interpretation. Try. p = Pattern.compile ("\\\\u0026"); But a simple replace should suffice (it doesn't use regex), with only one iteration of escape the backslash, for Java: ret = map.replace ("\\u0026", "&"); how can i make my garage cooler